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Unformatted text preview: Homework 4 Solution (ECE220  Fall 2007) 1. (25 points) Convolution and power The auto correlation function is defined as: R x [ l ] , X k = x * [ k ] x [ k + l ] R x ( ) , Z +  x * ( t ) x ( t + ) dt. There was an error on the homework set, it should have been dt not d . (a) (10 points) Show that for any signal x [ n ], R x [0] = E x and that similarly, for analog signals x ( t ), R x (0) = E x . Solution: R x [0] = X k = x * [ k ] x [ k + 0] = X k =  x [ k ]  2 = E x R x (0) = Z +  x * ( t ) x ( t + 0) dt = Z +   x ( t )  2 dt = E x (b) (10 points) The following series of equations is the proof of the following lemma. Lemma Let a signal have x [ n ] autocorrelation R x [ l ] and an LTI system with impulse response h [ n ] have autocorrelation R h [ l ]. Then: R y [ l ] = R h [ l ] * R x [ l ] . (1) Proof: R y [ l ] = + X n = y * [ n ] y [ n + l ] (2) = + X n = + X k = h * [ k ] x * [ n k ] ! + X m = h [ m ] x [ n + l m ] ! (3) ( m = k + p ) z}{ = + X p = + X k = h * [ k ] h [ k + p ] ! + X n = x * [ n k ] x [ n k + l p ] ! (4) ( v = n k ) z}{ = ... (5) = R h [ l ] * R x [ l ] . (6) q.e.d. Say why you can go from (2) to (3). Say what property of products and sums is used, in addition to the change of variable m = k + p , to go from (3) to (4). Complete the right, to go from (3) to (4)....
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This note was uploaded on 05/31/2008 for the course ECE 2200 taught by Professor Johnson during the Fall '05 term at Cornell University (Engineering School).
 Fall '05
 JOHNSON

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