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HWCh26Solutions

# HWCh26Solutions - Physics 133 Home work solutions Chapter...

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Unformatted text preview: Physics 133 Home work solutions Chapter 26 P26.1 (a) Q = C ∆ V = 4.00 × 10- 6 F ( 29 12.0 V ( 29 = 4.80 × 10- 5 C = 48.0 μ C (b) Q = C ∆ V = 4.00 × 10- 6 F ( 29 1.50 V ( 29 = 6.00 × 10- 6 C = 6.00 μ C P26.7 (a) ∆ V = Ed E = 20.0 V 1.80 × 10- 3 m = 11.1 kV m (b) E = σ ∈ σ = 1.11 × 10 4 N C ( 29 8.85 × 10- 12 C 2 N ⋅ m 2 ( 29 = 98.3 nC m 2 (c) C = ∈ A d = 8.85 × 10- 12 C 2 N ⋅ m 2 ( 29 7.60 cm 2 ( 29 1.00 m 100 cm ( 29 2 1.80 × 10- 3 m = 3.74 pF (d) ∆ V = Q C Q = 20.0 V ( 29 3.74 × 10- 12 F ( 29 = 74.7 pC P26.19 C p = C 1 + C 2 1 C s = 1 C 1 + 1 C 2 Substitute C 2 = C p- C 1 1 C s = 1 C 1 + 1 C p- C 1 = C p- C 1 + C 1 C 1 C p- C 1 ( 29 . Simplifying, C 1 2- C 1 C p + C p C s = . C 1 = C p ± C p 2- 4 C p C s 2 = 1 2 C p ± 1 4 C p 2- C p C s We choose arbitrarily the + sign. (This choice can be arbitrary, since with the We choose arbitrarily the + sign....
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HWCh26Solutions - Physics 133 Home work solutions Chapter...

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