HWCh25Solutions

HWCh25Solutions - Physics 133 Homework solutions Chapter 25...

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Unformatted text preview: Physics 133 Homework solutions Chapter 25 P25.2 K = q V 7.37 10- 17 = q 115 ( 29 q = 6.41 10- 19 C P25.4 W = K = - q V - 1 2 9.11 10- 31 kg ( 29 4.20 10 5 m s ( 29 2 = - - 1.60 10- 19 C ( 29 V From which, V = - 0.502 V . P25.7 U = - 1 2 m v f 2- v i 2 ( 29 = - 1 2 9.11 10- 31 kg ( 29 1.40 10 5 m s ( 29 2- 3.70 10 6 m s ( 29 2 = 6.23 10- 18 J U = q V : + 6.23 10- 18 = - 1.60 10- 19 ( 29 V V = - 38.9 V. The origin is at highest potential. P25.18 (a) E x = k e q 1 x 2 + k e q 2 x- 2.00 ( 29 2 = becomes E x = k e + q x 2 +- 2 q x- 2.00 ( 29 2 = . Dividing by k e , 2 qx 2 = q x- 2.00 ( 29 2 x 2 + 4.00 x- 4.00 = ....
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This note was uploaded on 06/02/2008 for the course PHY 133 taught by Professor K during the Fall '08 term at Cal Poly Pomona.

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HWCh25Solutions - Physics 133 Homework solutions Chapter 25...

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