HWCh29Solutions

# HWCh29Solutions - Physics 133 Homework solutions Chapter 29...

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Unformatted text preview: Physics 133 Homework solutions Chapter 29 P29.5 F = ma = 1.67 × 10- 27 kg ( 29 2.00 × 10 13 m s 2 ( 29 = 3.34 × 10- 14 N = qvB sin 90 ° B = F qv = 3.34 × 10- 14 N 1.60 × 10- 19 C ( 29 1.00 × 10 7 m s ( 29 = 2.09 × 10- 2 T The right-hand rule shows that B must be in the - y direction to yield a force in the + x direction when v is in the z direction. FIG. P29.5 P29.10 q E = - 1.60 × 10- 19 C ( 29 20.0 N C ( 29 ˆ k = - 3.20 × 10- 18 N ( 29 ˆ k F ∑ = q E + q v × B = m a- 3.20 × 10- 18 N ( 29 ˆ k - 1.60 × 10- 19 C 1.20 × 10 4 m s ˆ i ( 29 × B = 9.11 × 10- 31 ( 29 2.00 × 10 12 m s 2 ( 29 ˆ k - 3.20 × 10- 18 N ( 29 ˆ k - 1.92 × 10- 15 C ⋅ m s ( 29 ˆ i × B = 1.82 × 10- 18 N ( 29 ˆ k 1.92 × 10- 15 C ⋅ m s ( 29 ˆ i × B = - 5.02 × 10- 18 N ( 29 ˆ k The magnetic field may have any x-component ....
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## This note was uploaded on 06/02/2008 for the course PHY 133 taught by Professor K during the Fall '08 term at Cal Poly Pomona.

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HWCh29Solutions - Physics 133 Homework solutions Chapter 29...

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