HWCh27Solutions

# HWCh27Solutions - Physics 133 Homework solutions Chapter 27...

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Unformatted text preview: Physics 133 Homework solutions Chapter 27 P27.1 I = ∆ Q ∆ t ∆ Q = I ∆ t = 30.0 × 10- 6 A ( 29 40.0 s ( 29 = 1.20 × 10- 3 C N = Q e = 1.20 × 10- 3 C 1.60 × 10- 19 C electron = 7.50 × 10 15 electrons P27.14 (a) Applying its definition, we find the resistance of the rod, R = ∆ V I = 15.0 V 4.00 × 10- 3 A = 3 750 Ω = 3.75 k Ω . (b) The length of the rod is determined from the definition of resistivity: R = ρ l A . Solving for l and substituting numerical values for R , A , and the value of ρ given for carbon in Table 27.1, we obtain l = RA ρ = 3.75 × 10 3 Ω ( 29 5.00 × 10- 6 m 2 ( 29 3.50 × 10- 5 Ω ⋅ m ( 29 = 536 m . P27.15 ∆ V = IR and R = ρ l A : A = 0.600 mm ( 29 2 1.00 m 1 000 mm 2 = 6.00 × 10- 7 m 2 ∆ V = I ρ l A : I = ∆ VA ρ l = 0.900 V ( 29 6.00 × 10...
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## This note was uploaded on 06/02/2008 for the course PHY 133 taught by Professor K during the Fall '08 term at Cal Poly Pomona.

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HWCh27Solutions - Physics 133 Homework solutions Chapter 27...

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