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HWCh31Solutions

# HWCh31Solutions - Physics 133 Homework solutions Chapter 31...

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Physics 133 Homework solutions Chapter 31 Fall 2007 P31.1    ε= ∆Φ B t = NBA ( 29 t = 500 mV P31.12    ε = ∆Φ B t = N dB dt A = N 0.010 0 + 0.080 0 t ( 29 A At    t = 5.00 s ,    = 30.0 0.410  T s ( 29 π 0.040 0 m ( 29 2 = 61.8 mV P31.17 In a toroid, all the flux is confined to the inside of the toroid.    B = μ 0 NI 2 r = 500 0 I 2 r    Φ B = BdA = 500 0 I max 2 sin ϖ t adr r    Φ B = 500 0 I max 2 a sin t ln b + R R    ε=′ d Φ B dt = 20 500 0 I max 2 ϖ a ln b + R R cos t FIG. P31.17    10 4 2 4 π× 10 - 7   N A 2 ( 29 50.0 A ( 29 377  rad s ( 29 0.0200 m ( 29 ln 3.00 + 4.00 ( 29  cm 4.00 cm cos t = 0.422 V ( 29 cos t P31.20    I = R = B l v R    v = 1.00  m s FIG. P31.20 P31.26    ε=- N d dt BA cos θ=- NB cos θ A t    1 0.100 T ( 29 cos 0 ° 3.00 m

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HWCh31Solutions - Physics 133 Homework solutions Chapter 31...

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