Open Inquiry Report - Lab Partners Estrella Siedenburg Ashlin Chavez and Mikalah Millheim Open Inquiry Experiment II Enthalpy Change vs Amount of KOH

Open Inquiry Report - Lab Partners Estrella Siedenburg...

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Lab Partners: Estrella Siedenburg, Ashlin Chavez, and Mikalah Millheim Open Inquiry Experiment II November 18, 2015 Enthalpy Change vs. Amount of KOH reactant used Introduction Procedure Data and Interpretation By observing temperature change in H 2 SO 4 (aq) when KOH(s) was added, the change in enthalpy of the system and reaction could be calculated. When higher levels of potassium hydroxide were
added a greater change in temperature was observed. This also caused a greater change in enthalpy. The reaction was determined to be exothermic because there was a gain of heat in the H 2 SO 4 (aq) when KOH(s) was added. This can also be shown mathematically using the equation: H ? rxn = -(m x C s x T) ? A sample calculation with this equation using information known about H 2 SO 4 (aq) would appear as: Using trial #2 as the example H ? rxn = -(m x C s x T) ? + substitute “m” with mass of H 2 SO 4 (aq) =- (9.803 x 4.184 x 2.40) + assume C s of H 2 SO 4 (aq) is the same as H 2 O =-(98.407) kJ/ .01785 mol KOH + insert corresponding change in temperature =-(98.407) / .01786 + divide by #mole KOH to get kJ/ mol KOH = - 5511 kJ/mole KOH

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• Fall '16
• Christine Gaudinski
• Chemistry, Enthalpy, Reagent, Sodium hydroxide, mol KOH

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