# biochem lab 2 - Result Table 1 g BSA 0 10 20 30 40 50 l of...

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Result Table 1: μg BSA μl of BSA 2mg/ml stock solution μl H 2 0 added ml Bradford Reagent Absorbance 0 0 50 1.5 0.0045 10 5 45 1.5 0.106 20 10 40 1.5 0.243 30 15 35 1.5 0.324 40 20 30 1.5 0.587 50 25 25 1.5 0.711 Absorbance of Sample Concentration of protein (mg) Absorbance 0 0.0045 10 0.106 20 0.243 30 0.324 40 0.587 50 0.711 Unknown 0.393 Figure 1:

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Calculation Concentration of protein Calculations Abs= 0.393 (Jackbean extract) y = mx + b y =0.0136x 0.393 = 0.0136x x = 89 . 28 0136 . 0 393 . 0 = = 28.89 µg/protein Protein concentration in mg/ml extract Volume= 25 µl 1 ml = 1000 µl To convert = l g x l g x υ 1000 25 =
= l g x l µ 1000 µ µ 25 µg 28.89 = = 1155.6 µg/ml = 1155.6 * 10 = 11556 µg/ml To convert to mg/ml = 11.556 1000 11556 = = 11.556mg/ml (Protein conc.) To convert to mg mg ml ml mg 8 . 557 50 * 11.556 = Enzyme activity 50 5 min / µ 00736 . 0 min / µ 00736 . 0 min 5 0.0368µ 0.0368µ µ 10 * 10 68 . 3 10 68 . 3 10 3 . 2 * mol/L 1.6x10 mol/L 1.6x10 1 * 18885M 0.306 b A c bc 6 8 8 3 5 - 5 - 1 1 - x x mols mols s mols units mol mol mol mol x mol x L x cm cm c A = = = = = = = = = = - - - - - ε Enzyme Activity A= εbc A= 0.292 b = 1 cm ε = 18885 M -1 cm -1 c=?

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b A C
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biochem lab 2 - Result Table 1 g BSA 0 10 20 30 40 50 l of...

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