HW5Solutions - UNIVERSITY OF CALIFORNIA BERKELEY Spring 2016 Department of Civil and Environmental Engineering Instructor J P Moehle CE 120 Structural

HW5Solutions - UNIVERSITY OF CALIFORNIA BERKELEY Spring...

This preview shows page 1 - 3 out of 5 pages.

UNIVERSITY OF CALIFORNIA, BERKELEY Spring 201 6 Department of Civil and Environmental Engineering Instructor: J. P. Moehle CE 120 - Structural Engineering Solutions of Assignment No. 5 Due: February 2 6 , 201 6 Solution: ! Dead Load from ASCE-7-10 (Table C-3-1): Component Load(psf) Four ply felt and gravel 5.5psf Mechanical Duct 4psf ¾ ” Subflooring (plywood) 3psf ! Live loads 20psf ! Material Density: Douglas fir 34pcf Fig: Schematic Drawing of the Roof. (a) Loads Supported by Plywood: ¾ in plywood carries weight from everything above it and it’s self weight. Table 1: Loads carried by plywood Dead load Live load Four ply felt and gravel =5.5psf Roof Live load =20psf ¾ ” Plywood =3psf Total = 8.5 psf [ = 7.9psf] =20psf (b) Loads Supported by Joist: Joist supports loads that are on the plywood (from part a) , mechanical duct and its self-weight. Self-weight of joist: Actual dimensions of 2X10 Douglas Fir roof joist are 1.5”X 9.25” Therefore self-weight= (34pcf)*(1.5/12 ft)*(9.25/12 ft) = 3.27plf [OR: ¾” Plywood =0.4psf/(1/8")*(3/4")=2.4psf]
Image of page 1
Page 2 UNIVERSITY OF CALIFORNIA, BERKELEY
Image of page 2
Image of page 3

You've reached the end of your free preview.

Want to read all 5 pages?

  • Spring '09
  • Mario
  • Civil Engineering, Department of Civil Engineering, University of California, Construction terminology, J. P. Moehle

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture