This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Ph1a Solutions 8 Chefung Chan (cchan@caltech.edu), Fall 2007 Each homework problem is worth 5 points. Please disregard the point values listed on the problem itself. Use these instead. 8.1 FP3 (5 points) 8.1.a (2 points) The volume flow rate must be constant which implies ( vA ) hose = ( vA ) end , where v is the speed of the fluid and A is the cross sectional area. Since A end = 1 / 2 A hose , v end = 2 v hose = 2 * 5 m / s = 10 m / s. 8.1.b (3 points) First, change units to SI units: P end = 1 atm = 1 10 5 Pa, P hose = 0 . 5 atm = 5 10 4 Pa. Bernoullis equation gives: P end + 1 / 2 v 2 end + gy end = P top + 1 / 2 v 2 top + gy top y top = 1 g ( P end P top ) + 1 2 g ( v 2 end v 2 top ) + y end = 1 10 5 Pa . 5 10 5 Pa (6 10 3 kg / m 3 )(10 m / s 2 ) + (10 m / s) 2 (5 m / s) 2 2 * 10 m / s 2 + 0 = 5 m 8.2 FP11 (5 points) 8.2.a (1 point) The force of gravity is balanced by the bouyant force from the submerged fraction of the cube. If d is the depth of the bottom face, we have:...
View
Full
Document
 Fall '07
 Goodstein
 Work

Click to edit the document details