HW#1 Solutions
Problem 1.
R=
Λ
/M
gas
=49,700 ft
⋅
lbf/(slugmol
⋅°
R) / 28/mol = 1775 ft
⋅
lbf/(slug
⋅°
R)
ρ
=p/(RT)=2500 lb/ft
2
/(1775 ft
⋅
lbf/(slug
⋅°
R)
×
750
°
R) =
= 0.0018779 slug/ft
3
γ
=
ρ
g = 0.0018779 slug/ft
3
×
32.174 ft/s
2
= 0.0604 lbf/ ft
3
Problem 2.
∑
−
=
=
bottom
x
A
W
F
τ
θ
sin
0
T
T
s
kg
m
s
m
kg
dy
d
υ
υ
υ
µ
τ
⋅
=
⎟
⎟
⎠
⎞
⎜
⎜
⎝
⎛
⋅
=
⎟
⎟
⎠
⎞
⎜
⎜
⎝
⎛
=
)
/
(
7
.
33
003
.
0
)
/
(
104
.
0
2
2
3
.
0
)
/
(
7
.
33
15
sin
/
81
.
9
18
m
s
kg
s
m
kg
T
⋅
⋅
−
°
⋅
⋅

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