ch06 - CHAPTER SIX 6.1 a. AB: Heat liquid - V constant BC:...

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CHAPTER SIX 6.1 a . AB: Heat liquid -- constant V o BC: Evaporate liquid -- increases, system remains at point on vapor-liquid equilibrium curve as long as some liquid is present. 100 C. V T = CD: Heat vapor - -T increases, V increases. b. Point B : Neglect the variation of the density of liquid water with temperature, so ρ = 1.00 g/mL B and 10 mL V = Point C : H 2 O (v, 100 ° C) 10 mL 1.00 g 1 mol 0.555 mol mL 18.02 g n == 0.555 mol 0.08206 L atm 373 K 17 L 1 atm mol K C CC C C C nRT PV nRT V P =⇒ = = = 6.2 a . mm Hg final P = 243 . Since liquid is still present, the pressure and temperature must lie on the vapor-liquid equilibrium curve, where by definition the pressure is the vapor pressure of the species at the system temperature. b . Assuming ideal gas behavior for the vapor, m(vapor) (3.000-0.010) L mol K 243 mm Hg 1 atm 119.39 g (30 + 273.2) K 0.08206 L atm 760 mm Hg mol g = = 459 . m(liquid) 10 mL 1.489 g mL g 1489 . m m(vapor) + m(liquid) =19.5 g total = x= 4.59 g vapor / g total vapor 19 48 0235 . . = 6.3 a. log . . .. *. 3 7 0 10 2 709808 123871 45 217 2370 10 2345 pp =− + mm Hg b. ln ±± ln / ln / . ** .0 . p H RT B H R vv TT ++ + ⇒− = = ∆∆ 1 760 1183 4151 21 5 di bg 11 1 77 273.2 K 1 29 273.2 K K Bp HR T v = +=+ + = ln( ) ± / ln . . * 1 1 1183 1849 4151 K 29.5 273.2 K 6- 1
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6.3 (cont’d) ln ( . . .. . . pp ∗∗ =− + +⇒ = ×= 45 1849 2310 2345 100% 15% o C) 4151 45 273.2 mm Hg error bg c. p = F H G I K J −+= 1183 760 295 77 45 327.7 mm H . . g 3277 100% 39 7% . . error 6.4 Plot p + log . scale vs 1 T 2732 (rect. scale) on semilog paper straight line: slope = 7076 2167 K , intercept . ln . .e x p . . p T p T = + = + + L N M O Q P mm Hg 7076 (C ) 7076 ) oo 2732 2167 2732 2167 H R v = 7076K ± H v = = 7076 K 8.314 J 1 kJ mol K 10 J 58.8 kJ mol 3 6.5 ln p* = A/T(K) + B T( o C) p*(mm Hg) 1/T(K) ln(p*) p*(fitted) T( o C) p*(fitted) 79.7 5 0.002834 1.609 5.03 50 0.80 105.8 20 0.002639 2.996 20.01 80 5.12 120.0 40 0.002543 3.689 39.26 110 24.55 141.8 100 0.002410 4.605 101.05 198 760.00 178.5 400 0.002214 5.991 403.81 230 2000.00 Least confidence 197.3 760 0.002125 6.633 755.13 (Extrapolated) y = -7075.9x + 21.666 0 1 2 3 4 5 6 7 0.002 0.0022 0.0024 0.0026 0.0028 0.003 1/T ln(p*) 6- 2
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6.6 a. T(°C) 1/T(K) p * (mm Hg) =758.9 + h right -h left 42.7 3.17 × 10 -3 34.9 58.9 3.01 × 10 -3 78.9 68.3 2.93 × 10 -3 122.9 77.9 2.85 × 10 -3 184.9 88.6 2.76 × 10 -3 282.9 98.3 2.69 × 10 -3 404.9 105.8 2.64 × 10 -3 524.9 b. Plot is linear, ln ± ln . . p H RT Bp K T v ∗=− + ∗= + 51438 19855 At the normal boiling point, pT b = ° 760 116 mmHg C ± H v = = 8.314 J 5143.8 K 1 kJ mol K 10 J 42.8 kJ mol 3 c. Yes — linearity of the ln plot over the full range implies validity. / p vs 1 T 6.7 a. ln . ln ; . pa T bya xby px T + + = + = = + 2732 1 bg Perry's Handbook, Table 3-8: T , , 1 395 .C 11 3 400 31980 10 = × mm Hg . y 1 599146 = . T , , 2 565 22 3 760 30331 10 = × mm Hg . y 2 663332 = Tx =°⇒= × 50 30941 10 3 C. yy xx p e =+ F H G I K J −= ∗°= = 1 1 21 6.39588 639588 50 599 b g .C m m H g b. 50 122 °= ° CF Cox Chart psi 760 mm Hg 14.6 psi mm Hg ⇒∗ = = p 12 625 c. log . . . .7872 pp + =⇒ = = 702447 11610 50 224 27872 10 613 2 mm Hg 6.8 Estimate Assume a TK b ∗° = + 35 : ln , interpolate given data. a bp a T p pe TT = ∗∗ = =− =∗ = + + = U V | | W | | ∗° = + += = ++ ln ln . ln ln . . . ln . . .. . .2 .2 .630 1 45 273 1 25 273 1 1 4 200 50 65771 50 25 2597 35 35 4630 35 1025 b g C C mm Hg 6- 3
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6.8 (cont’d) Moles in gas phase: 150 mL 273 K 102.5 mm Hg 1 L 1 mol 35+ 273.2 K 760 mm Hg 10 m 22.4 L STP mol 3 n L = bg b 80 10 4 .
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This note was uploaded on 06/07/2008 for the course CHE 2171 taught by Professor Wetzel during the Spring '08 term at LSU.

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ch06 - CHAPTER SIX 6.1 a. AB: Heat liquid - V constant BC:...

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