MidtermAnsOnly_000

MidtermAnsOnly_000 - BIMM110 Name Spring 2008 Subramani 1...

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Unformatted text preview: BIMM110 Name: Spring 2008 Subramani 1 MIDTERM EXAM ANSWERS 1a. (3 points) iii. 1b. 1b. (3 points) Circled individuals must be heterozygotes; affected individuals (filled symbols) are homozygotes. 1c. (3 points) ii. 1d. (3 points) (i) 0 (ii) All 2a. (3 points) Autosomal recessive. 2b. (4 points) Genetic heterogeneity in the cause of deafness. The gene affected in the two families is different so that children are heterozygous for two different disease loci. 2c. (3 points) In this case the STR linked to one gene will not work for the other gene, unless linkage is shown. A LOD score can be calculated with the STR for family 2, but it is unlikely to show a LOD score of 3 or above. LOD scores for the two families cannot be added because they are not tracking the same disease gene. 3a. (3 points) New mutation. This is an autosomal dominant disease, which you should have remembered from the assignment and class notes. Even if you did not remember this, a clue that it must be dominant is that you never get a disease from a new mutation for a recessive disorder because two such mutations would be needed. new mutation for a recessive disorder because two such mutations would be needed....
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MidtermAnsOnly_000 - BIMM110 Name Spring 2008 Subramani 1...

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