36.(a) For the minimum (43 cm) case, 9 cubit converts as follows:(9 cubit)µ0.43 m1 cubit¶=3.9m.And for the maximum (43 cm) case we obtain(9 cubit)µ0.53 m1 cubit¶=4.8m.(b) Similarly, with 0.43 m→430 mm and 0.53 m→530 mm, we ±nd 3.9×103mm and 4.8×103mm,respectively.(c) We can convert length and diameter ±rst and then compute the volume, or ±rst compute the volume
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 06/11/2008 for the course PHY 036 taught by Professor Furlan during the Spring '08 term at UniFor.