36.
(a) For the minimum (43 cm) case, 9 cubit converts as follows:
(9 cubit)
µ
0
.
43 m
1 cubit
¶
=3
.
9m
.
And for the maximum (43 cm) case we obtain
(9 cubit)
µ
0
.
53 m
1 cubit
¶
=4
.
8m
.
(b) Similarly, with 0
.
43 m
→
430 mm and 0
.
53 m
→
530 mm, we ±nd 3
.
9
×
10
3
mm and 4
.
8
×
10
3
mm,
respectively.
(c) We can convert length and diameter ±rst and then compute the volume, or ±rst compute the volume
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This note was uploaded on 06/11/2008 for the course PHY 036 taught by Professor Furlan during the Spring '08 term at UniFor.
 Spring '08
 FURLAN

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