p01_036 - 36(a For the minimum(43 cm case 9 cubit converts...

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36. (a) For the minimum (43 cm) case, 9 cubit converts as follows: (9 cubit) µ 0 . 43 m 1 cubit =3 . 9m . And for the maximum (43 cm) case we obtain (9 cubit) µ 0 . 53 m 1 cubit =4 . 8m . (b) Similarly, with 0 . 43 m 430 mm and 0 . 53 m 530 mm, we ±nd 3 . 9 × 10 3 mm and 4 . 8 × 10 3 mm, respectively. (c) We can convert length and diameter ±rst and then compute the volume, or ±rst compute the volume
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This note was uploaded on 06/11/2008 for the course PHY 036 taught by Professor Furlan during the Spring '08 term at UniFor.

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