p01_037 - πr 2 h = π (3 . 00) 2 (5 . 50) = 155 . 5 ken 3...

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37. (a) Squaring the relation 1 ken = 1 . 97 m, and setting up the ratio, we obtain 1ken 2 1m 2 = 1 . 97 2 m 2 1m 2 =3 . 88 . (b) Similarly, we fnd 1ken 3 1m 3 = 1 . 97 3 m 3 1m 3 =7 . 65 . (c) The volume oF a cylinder is the circular area oF its base multiplied by its height. Thus,
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Unformatted text preview: πr 2 h = π (3 . 00) 2 (5 . 50) = 155 . 5 ken 3 . (d) IF we multiply this by the result oF part (b), we determine the volume in cubic meters: (155 . 5)(7 . 65) = 1 . 19 × 10 3 m 3 ....
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This note was uploaded on 06/11/2008 for the course PHY 037 taught by Professor Furlan during the Spring '08 term at UniFor.

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