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37.
(a) Squaring the relation 1 ken = 1
.
97 m, and setting up the ratio, we obtain
1ken
2
1m
2
=
1
.
97
2
m
2
1m
2
=3
.
88
.
(b) Similarly, we fnd
1ken
3
1m
3
=
1
.
97
3
m
3
1m
3
=7
.
65
.
(c) The volume oF a cylinder is the circular area oF its base multiplied by its height. Thus,
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Unformatted text preview: πr 2 h = π (3 . 00) 2 (5 . 50) = 155 . 5 ken 3 . (d) IF we multiply this by the result oF part (b), we determine the volume in cubic meters: (155 . 5)(7 . 65) = 1 . 19 × 10 3 m 3 ....
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This note was uploaded on 06/11/2008 for the course PHY 037 taught by Professor Furlan during the Spring '08 term at UniFor.
 Spring '08
 FURLAN

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