p01_007 - µ 10 3 m 1 km ¶µ 10 2 cm 1 m = 2000 × 10 5...

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7. The volume of ice is given by the product of the semicircular surface area and the thickness. The semicircle area is A = πr 2 / 2, where r is the radius. Therefore, the volume is V = π 2 r 2 z where z is the ice thickness. Since there are 10 3 min1kmand10 2 cm in 1 m, we have r = (2000 km)
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Unformatted text preview: µ 10 3 m 1 km ¶µ 10 2 cm 1 m ¶ = 2000 × 10 5 cm . In these units, the thickness becomes z = (3000 m) µ 10 2 cm 1 m ¶ = 3000 × 10 2 cm . Therefore, V = π 2 ( 2000 × 10 5 cm ) 2 ( 3000 × 10 2 cm ) = 1 . 9 × 10 22 cm 3 ....
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This note was uploaded on 06/11/2008 for the course PHY 007 taught by Professor Furlan during the Spring '08 term at UniFor.

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