Fundamentals Of Physics (6ºed)\chap01

# Fundamentals Of Physics (6ºed)\chap01 - V = M ρ = 9 27...

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23. We introduce the notion of density (which the students have probably seen in other courses): ρ = m V and convert to SI units: 1000 g = 1 kg, and 100 cm = 1 m. (a) The density ρ of a sample of iron is therefore ρ = ³ 7 . 87 g / cm 3 ´ µ 1kg 1000 g ¶µ 100 cm 1m 3 which yields ρ = 7870 kg/m 3 . If we ignore the empty spaces between the close-packed spheres, then the density of an individual iron atom will be the same as the density of any iron sample. That is, if M is the mass and V is the volume of an atom, then
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Unformatted text preview: V = M ρ = 9 . 27 × 10 − 26 kg 7 . 87 × 10 3 kg / m 3 = 1 . 18 × 10 − 29 m 3 . (b) We set V = 4 πR 3 / 3, where R is the radius of an atom (Appendix E contains several geometry formulas). Solving for R , we Fnd R = µ 3 V 4 π ¶ 1 / 3 = µ 3(1 . 18 × 10 − 29 m 3 ) 4 π ¶ 1 / 3 = 1 . 41 × 10 − 10 m . The center-to-center distance between atoms is twice the radius, or 2 . 82 × 10 − 10 m....
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## This note was uploaded on 06/11/2008 for the course PHY 023 taught by Professor Furlan during the Spring '08 term at UniFor.

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