Unformatted text preview: V = M ρ = 9 . 27 × 10 − 26 kg 7 . 87 × 10 3 kg / m 3 = 1 . 18 × 10 − 29 m 3 . (b) We set V = 4 πR 3 / 3, where R is the radius of an atom (Appendix E contains several geometry formulas). Solving for R , we Fnd R = µ 3 V 4 π ¶ 1 / 3 = µ 3(1 . 18 × 10 − 29 m 3 ) 4 π ¶ 1 / 3 = 1 . 41 × 10 − 10 m . The centertocenter distance between atoms is twice the radius, or 2 . 82 × 10 − 10 m....
View
Full
Document
This note was uploaded on 06/11/2008 for the course PHY 023 taught by Professor Furlan during the Spring '08 term at UniFor.
 Spring '08
 FURLAN
 Physics

Click to edit the document details