Fundamentals Of Physics (6ºed)\chap01

# Fundamentals Of Physics (6ºed)\chap01 - M = ρV(the...

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21. We introduce the notion of density (which the students have probably seen in other courses): ρ = m V and convert to SI units: 1 g = 1 × 10 3 kg. (a) For volume conversion, we ±nd 1 cm 3 =(1 × 10 2 m) 3 =1 × 10 6 m 3 . Thus, the density in kg/m 3 is 1g / cm 3 = µ 1g cm 3 ¶µ 10 3 kg g ¶µ cm 3 10 6 m 3 =1 × 10 3 kg / m 3 . Thus, the mass of a cubic meter of water is 1000 kg. (b) We divide the mass of the water by the time taken to drain it. The mass is found from
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Unformatted text preview: M = ρV (the product of the volume of water and its density): M = (5700 m 3 )(1 × 10 3 kg / m 3 ) = 5 . 70 × 10 6 kg . The time is t = (10 h)(3600 s / h) = 3 . 6 × 10 4 s, so the mass ﬂow rate R is R = M t = 5 . 70 × 10 6 kg 3 . 6 × 10 4 s = 158 kg / s ....
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