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Unformatted text preview: 6 m (metric preFxes can be found in Table 12), we obtain A = 1 . 430 × 10 − 6 m 3 1 × 10 − 6 m = 1 . 430 m 2 . (b) The volume of a cylinder of length ` is V = A` where the crosssection area is that of a circle: A = πr 2 . Therefore, with r = 2 . 500 × 10 − 6 m and V = 1 . 430 × 10 − 6 m 3 , we obtain ` = V πr 2 = 7 . 284 × 10 4 m ....
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This note was uploaded on 06/11/2008 for the course PHY 020 taught by Professor Furlan during the Spring '08 term at UniFor.
 Spring '08
 FURLAN
 Physics

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