Fundamentals Of Physics (6ºed)\chap01

Fundamentals Of Physics (6ºed)\chap01 - t C − t C = 2 7...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
14. The time on any of these clocks is a straight-line function of that on another, with slopes 6 =1and y -intercepts 6 = 0. From the data in the ±gure we deduce t C = 2 7 t B + 594 7 t B = 33 40 t A 662 5 . These are used in obtaining the following results. (a) We ±nd t 0 B t B = 33 40 ( t 0 A t A ) = 495 s when t 0 A t A = 600 s. (b) We obtain
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: t C − t C = 2 7 ( t B − t B ) = 2 7 (495) = 141 s . (c) Clock B reads t B = (33 / 40)(400) − (662 / 5) ≈ 198 s when clock A reads t A = 400 s. (d) From t C = 15 = (2 / 7) t B + (594 / 7), we get t B ≈ − 245 s....
View Full Document

This note was uploaded on 06/11/2008 for the course PHY 014 taught by Professor Furlan during the Spring '08 term at UniFor.

Ask a homework question - tutors are online