Unformatted text preview: N = ft 1 Ã— 10 6 = Âµ 1 rotation 1 . 55780644887275 Ã— 10 âˆ’ 3 s Â¶ t which yields the result t = 1557 . 80644887275 s (though students who do this calculation on their calculator might not obtain those last several digits). (c) Careful reading of the problem shows that the timeuncertainty per revolution is Â± 3 Ã— 10 âˆ’ 17 s. We therefore expect that as a result of one million revolutions, the uncertainty should be ( Â± 3 Ã— 10 âˆ’ 17 )(1 Ã— 10 6 ) = Â± 3 Ã— 10 âˆ’ 11 s....
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This note was uploaded on 06/11/2008 for the course PHY 018 taught by Professor Furlan during the Spring '08 term at UniFor.
 Spring '08
 FURLAN
 Physics

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