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Unformatted text preview: N = ft 1 × 10 6 = µ 1 rotation 1 . 55780644887275 × 10 − 3 s ¶ t which yields the result t = 1557 . 80644887275 s (though students who do this calculation on their calculator might not obtain those last several digits). (c) Careful reading of the problem shows that the timeuncertainty per revolution is ± 3 × 10 − 17 s. We therefore expect that as a result of one million revolutions, the uncertainty should be ( ± 3 × 10 − 17 )(1 × 10 6 ) = ± 3 × 10 − 11 s....
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 Spring '08
 FURLAN
 Physics

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