Exam 1 key - CHEM 1212-02 Spring 20008 EXAM #1 -—...

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Unformatted text preview: CHEM 1212-02 Spring 20008 EXAM #1 -— WEDNESDAY JANUARY 30, 2008 . 12:30- 1:30 pm. ' Answer all questions. Mark your answers on the Scantron Sheet, using a #2 pencil. Be sure first to write your name on the Scantron sheet, in the place marked, using the format: Family Name, Space, First Name. There is only one correct answer for each question. Do not write on the Scantron sheet, other than to fill in the appropriate “bubble”. Do all your rough work on scratch paper. Do not rush your work! You have plenty of time to answer all the questions. Do your best and Good Luck! " 1. In the sublimation process, a substance passes directly between phases, without passing though the usual intermediate phase.The phase change refere'd to in this process is fi'om: _. Solid to gas (b) Liquid to solid e) solid to liquid (d) gas to solid (e) none of the aboye me” E” 354 50A: psi ‘30 11(57"? 0 co 1(0 6-5) SUE (4/77??le l i ’ ' the'temperature and the 2. The va or pressure exerted by a llquld dependson both . . strength of the intermolecular forces in the hquld. The relatl'onshlp between P and Th theforrn: as P=-AH/R(1/T)+C (B) P=-AH/R(1f1‘)+,C G)-1nP=AH/R ) +C (d) P = -AH/R ln (1/T) +C (e) none of these CLAUSIUS ~CLAP57/Low EQM. (.31 A13 ;_¢Hw(/L_,T P’ 4 7'2. x.“ We? Tile Foul or(a) /l 3. Hydrocarbons come in several classes, including alkanes, alkenes and cycloalkanes. Molecules with the general formula CnHZn are classified as: (a) cycloalkanes (b) alkanes ©) alkenes (d) alkenes and cycloalkanes. H H it \ / \C/ C5141; lCYCLoAcKAA/Eng C \ / \ \ C/ C / C" l \ __ ,Q .—~ /. C —-»— C’AH / 4 l C / \ x g C / I I Call an H H / \ / \ ,l C, —- C - C 3 HQ C l l / \ C H l l \ , ‘7‘ g C}: C "‘ C ”‘ C, :2 C, ' K \ \ocd d E C 3 6 (a H (pt / l‘ 1 C4 H3 ALK ENES 4. The alkane called Octane has the formula: (a)(é Hls (b) CJIH ©) CwI-I22 (d) C4H10 (e) none of these an I HeTHM/E g ALKAVE—j’: Ca” m+z Cpl-ho,- iEUY/mé C5 H17, "‘ Rea/AME C) H”) -—— PEN/("AME (WCN7A :9) C3 [4.3 —- 0C7/yL/E , (DC7D : The properties of water as a solvent are mainly due to its: (a) low volatility (b) hydrogen bonding ©) dispersion forces ((1) ' polarizability (e) none of these . 54 5 + A” l \ H H f TDfl’OCév-J \ /O'- ’C‘ Icy. E—nMD/mé IN I J: m “7‘” 'lhe Henry’s Law gas constant (kn) for O2 in water at 20 9C is 1.28 x 10imol/L atm. How many g. of oxygen will dissolve in 20 L of water in contact with pure oxygen at 1 atm.? (a) 0.0819g (b)8.19g ©) 0.1081 d 0.001’89 ‘ 11E?“ ,g ( ) g none of S: hi4 : ngwofs d I "g l 4* ‘ m1:/:%x ;£{ 2% : IVs/O, (mt/“(um Loam—H? of— OL‘; IZX/é'ooz 32430394" . .Qoiéé 0L :. 0.02.56 Mai. — )(ZZ-QOSMAII : 0. 51923 The colligative property which is probably most important in keeping living tissue healthy is: _ Osmotic pressure (b) fi'eezing point depression c) Vapor pressure reduction (d) capillary action €13. Mae—f cows. COW/xoL-K 147,0 Uokul'té IN cC/LLS rut/Lousy} oJHoj/S , (Va-r (Jag/(flour PLUID UOVV‘LG NV {5007 A NAME? Cow’Z/LQLJ 1105*. ‘. i, The mogality of a solution made by adding 1 kg of ethylene glycol (C2H602) to a car radiator containing 4450 mL of water is . . _ 3.62 m (b) 16.1 m c) 2.451 m (d) 1.85 m V (e) none ofthese . MOAAAJ77 '3 MOL. 0&IOLUT‘6 :75?" HoL m Clues/t I “23 C r T—l‘hoL-l- - f r 1 0-2.. .2 [logo 3 M. ('DQB-f-Z’dmoo (>243) :62‘°7 Q'KI-o. [((m/L) MSOML Hero 5 H450 ow? (A1 15°C] Dewgl’r7 O‘F’ HLOQ/Ijoc :— [-0030m~3 L'Q-S-QML Hut: : [LII-SO . (430 - [6.1 o, - W? a {m L 2 3-éZM-'.(q) o Lpuso ‘23 9. The depression of the freezing point of this water/antifreeze mixture, assuming a ‘ Kf of 1.86 0C /m is: ‘ ' (a) 4.55 °C @573 °C 0) 0.554 0C (d) 17.2 “C (6) none of these (37": Kai-xv? 7 2.36%;ch x 3.62% : é.73mC, (’3) 10. A rather polluted room contains air with 4.6 mol/L of CO. Hyou were in this room for 8.0 hours, and inhaled air at a rate of 12 L/min, you would inhale a C0 mass of: @748 kg (b) 748 g c) 3.31 kg (d) 5.52 kg ((1) none of these —_—. 77 Wu —/ C0 cwc. w PM. = 4.6msi .L INHALeh Pym, UOLOPLE /H/U :: IZL INHALE—D Am UOLUA/Lé no % lo‘Odéj = '2 LMWiSH/LL >< 50 “"0144” 2 5.760 “531‘ CO mi—Mbfig UV 8 HA5. 2 4-(9 MoLy’A x 5.”)éoxtbz/L/ 2 )qb‘f Hat. I Mot/ECULA‘JZ MA'Sd OF CO '2 25.0! Egrwnlifl ...
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This note was uploaded on 06/11/2008 for the course CHEM 1212 taught by Professor Dockery during the Spring '08 term at Kennesaw.

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Exam 1 key - CHEM 1212-02 Spring 20008 EXAM #1 -—...

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