Soln to Practice Final-1

Soln to Practice Final-1 - Soln to Practice Final 1) Count...

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Soln to Practice Final 1) Count over on the periodic table and Cr(0) in compounds has 6 d electrons (in compounds all the valence electrons are in the d orbitals) and Mn has 7 d electrons. The maximum oxidation states of 6+ and 7+ correspond to loss of all the valence electrons. 2) Dichoromate is hydrolyzed to chromate (CrO 4 2- ) as described in the text in basic solution. So answer A. 3) Oxalato is usually a bidentate ligand through the two negative oxygens, answer E. 4) The octahedral cation is [CoCl(NH 3 )] 2+ to balance the charge of the two chlorides. Since Cl is anionic and ammonia is neutral, the charge on Co must be 3+ (sum of the metal oxidation state and the charges of the bound ligands = charge on the ion). E 5) B, the ligands are in alphabetical order and since ethylenediamine contains a latin di prefix in it you use the greek bis to express the fact there are two ethylene diamines. It is not necessary to express the two chloride anions as dichloride, since it is clear there must be two of them from the charge on the cation. 6) D, Two the fac and mer isomers. 7) B, the cis complex has nonsuperimposable mirror images see http://www.public.asu.edu/~jpbirk/CHM-115_BLB/Chpt24/sld051.htm for structures. It is also the only compound that does not contain a mirror plane. 8) C, because the Cr is in the high +6 oxidation state. 9) D, the one with the highest cationic charge can better stabilize the OH - ligand produced when the aquo ion loses a proton. 10) B, because CN - is the strongest field ligand in the spectrochemical series compared to the other ligands. 11)
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This note was uploaded on 06/12/2008 for the course CHEM 6C taught by Professor Hoeger during the Spring '08 term at UCSD.

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Soln to Practice Final-1 - Soln to Practice Final 1) Count...

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