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**Unformatted text preview: **Quiz 5(Mar 5th): Pbl (5 pts): Evaluate the double integral imam, WhereR= [0, 2]><[— 1,2]. (Hint: V4 4—m2>0when 2—<:z;§2.) (1952 (/15qu [an nut be mammal ﬁxedly)
541mg); N371 20 war R
¢7jgn70lAz Me WOIMN aver-)2 Mm WWW A? Pb2 (5 pts): Given that D IS the region bounded by y— — ac — 1 and :2:— — y.2 Set
up the double integral // ydA, as an iterated integral Do not evaluate. 62 W1: (m7. two min/rm tomb FXE Quiz 6(Mar 12th): Pbl (5 pts): Evaluate the double integral // (3:2 —|— y2)3/2 dA, Where D is the
D region in the ﬁrst quadrant bounded by the lines y = a: and y = ﬁst: and the circle
$2 + 3/2 = ' y M“ yzx z? tan9'—l 4.») (9:227
”* Wm: tunnaNié“? (9:175, ﬁozﬂwﬂﬁiﬁlg/ osrsfj
2 3' § 2 3 ﬂ 2) '1
SgtxﬁHdAzlérlo (rt)? retrain-[g Y‘LlclwlLS’ 7:.
= S? Hamlm 01w Lari-3149: %e~%a=1:é~i—; ‘ Pb2 (5 pts): Find the value of constant C', so that f is a joint density function. _ Ce_(5x+2y) if ix 2 0,3; 2 0
f(:17,y) — { 0 otherwise WmaoaCm-
SECS 9W WM a -
lﬁﬁb; ¥l%\\3\d\;¢ly: g2“ WOewlwaI—wdydx : 6700002312, ”CAM"
_..~~ y: .7, V360
‘C'lgofm‘x' [50(7’943—20 FliQijlxmm‘ VJ; «ally; : c- E o— lit/77' {Li-Ha] : C1}? iaO-fssi _—£—> (1:210 l; Quiz 7 (Mar 26th): Pbl (5 pts): Find the area of the following surface:
the part of (the hyperbolic parabolid) z : y2 ~m2 that lies between the cylinders
x2+y2 : 1 and x2+y2 : 4. (Your ﬁnal answer can be left as without simpliﬁcation, such as 17%.) S: zagalxz‘
3%?w %r%' am at 8= 3g ‘(amgom AA 1 (g W: 01A
WWA Dzmm osgsm, \é r383.
79“” °i S = WWW i :1
; $0M [. ﬁwr‘ﬂf—llm Die 3
: {flﬁuz’i 5%)(19 = Q ll’] 4”) Pb2 (5 pts): T is the solid enclosed by the cylinder y : x2 and the planes z : 0
and y + z 2 1. Set up an iterated triple‘integral to evaluate the volume of-T. Do
not evaluate the integral. a 4
013099))! aéxa/ {9/447}, ,
T :4 we)! (mm oez a W3- Vilf' Ow {HUGH l 'd‘tdw ...

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- Fall '08
- Staff
- Multivariable Calculus