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# img019we2 - 20 Chapter 6 Applications of Integration 41:20...

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Unformatted text preview: 20 Chapter 6 Applications of Integration 41:20:): Jri—x1.:{x)=0 44.x=~/F5vy3.R(y)=Jr2-y2. rbr)=0 v = «Lu! - x2) ‘1; V = «KL/172775): ﬂy # l 5 = Zwﬁw - x“) dx ‘ 24 46 (a) V=1rJ (.5) dx=1rJ ”pkg-LAW (1:)de xdz=3—3l’(onemirdomwvolume).1hn 0 0 m0<c<4andset fi=ﬂc3=ﬁc=4=43 a mum: 2 3' 3' ﬁ 3' 1' ‘“'[T]n"2'=‘” .. 16-31- ° 'I'oﬁndtheothervalue seHrJ' xdx=—3-(twolhlrds r:1 = of the volume) Then “ ﬁﬁﬂﬂ 2211519.! d2=2d=£2=5ﬁ Thus.when:=2ﬁ.lhesolidisdividedinmtwo 2 3 ' 3' 3 3 ﬂux-values that divide the solid inmthmepartsof cqual parts of equal volume. volumearex = (4J§)/3 andx = (4J5)!3. ...
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