ReviewExam3Sp07_Practice

# ReviewExam3Sp07_Practice - Create assignment 93205 Homework...

This preview shows pages 1–4. Sign up to view the full content.

Create assignment, 93205, Homework 3, Apr 26 at 12:50 am 1 This print-out should have 40 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. version 728 CalC12c04a 55:03, calculus3, multiple choice, > 1 min, wording-variable. 001 Determine which of the following series are convergent: A . 1 + 1 4 + 1 9 + 1 16 + . . . B . X n = 1 3 n 2 + 1 C . X n = 1 2 n 3 / 2 1. C only 2. A and C only 3. all of them 4. none of them 5. B and C only 6. A only 7. B only 8. A and B only CalC12c15s 55:03, calculus3, multiple choice, < 1 min, wording-variable. 002 Determine whether the series X n = 1 1 n 2 + 4 converges or diverges. 1. series diverges 2. series converges CalC12c20a 55:03, calculus3, multiple choice, < 1 min, wording-variable. 003 Determine whether the series X m = 1 3 ln(4 m ) m 2 is convergent or divergent. 1. series converges 2. series diverges CalC12d15s 55:04, calculus3, multiple choice, > 1 min, wording-variable. 004 Determine whether the series X k = 1 6 + cos k 2 k converges or diverges. 1. series is convergent 2. series is divergent CalC12d19b

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Create assignment, 93205, Homework 3, Apr 26 at 12:50 am 2 55:04, calculus3, multiple choice, > 1 min, wording-variable. 005 Which of the following infinite series con- verges? 1. X n = 1 5 n 7 n + 4 n 2. X n = 1 7 5 n - 4 3. X k = 2 4 7 k ln k + 5 k 4. X n = 1 5 n n ( n + 5) n 5. X n = 1 5 4 n CalC12d34b 55:04, calculus3, multiple choice, > 1 min, wording-variable. 006 Which of the following series converge(s)? ( A ) X k = 2 4 k + 3 ( k ln k ) 2 + 6 ( B ) X n = 1 n - 7 n + 3 ( C ) X n = 1 7 n + 3 6 n - 4 n 1. C only 2. none of A, B, or C 3. A, B, and C 4. B and C 5. A and C 6. B only 7. A and B 8. A only CalC12e05s 55:05, calculus3, multiple choice, > 1 min, normal. 007 Which one of the following series is conver- gent? 1. X n = 1 3 5 + n 2. X n = 1 ( - 1) n - 1 1 + n 3. X n = 1 ( - 1) n - 1 1 + n 5 + n 4. X n = 1 ( - 1) 2 n 5 3 + n 5. X n = 1 ( - 1) 3 5 3 + n CalC12f04a 55:06, calculus3, multiple choice, < 1 min, normal. 008 Determine whether the series 4 8 - 4 9 + 4 10 - 4 11 + 4 12 - . . . is conditionally convergent, absolutely con- vergent, or divergent. 1. absolutely convergent 2. series is divergent 3. conditionally convergent CalC12f09s
Create assignment, 93205, Homework 3, Apr 26 at 12:50 am 3 55:06, calculus3, multiple choice, < 1 min, wording-variable. 009 Which one of the following properties does the series X n = 1 2 n + 3 (2 n )! have? 1. divergent 2. absolutely convergent 3. conditionally convergent CalC12f10s 55:06, calculus3, multiple choice, > 1 min, wording-variable. 010 Which one of the following properties does the series X n = 1 2 - n n ! have? 1. absolutely convergent 2. conditionally convergent 3. divergent CalC12f33b 55:06, calculus3, multiple choice, < 1 min, wording-variable. 011 Decide which of the following series con- verge(s) ( A ) X n = 1 n 8 n + 3 3 8 n ( B ) X n = 1 n - 4 n + 5 5 4 n ( C ) X n = 1 4 n + 5 n 3 + 8 n 1. C only 2. A and B 3. B only 4. all of them 5. A and C CalC12h05s 55:08, calculus3, multiple choice, > 1 min, normal.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern