EOC_Solution_02_55 - 2.55. Model: We will model the lead...

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2.55. Model: We will model the lead ball as a particle and use the constant-acceleration kinematic equations. Visualize: Note that the particle undergoes free fall until it hits the water surface. Solve: The kinematics equation yyv tt a 100 1 0 1 201 0 2 =+ −+ () becomes −= + + = 50 98 0 1 2 1 .( . ) ( ) m 0 m 0 m 1 2 m/s 1.01 s 2 Now, once again, a v 211 2 1 1 2 1 2 1 1 2 0 ⇒−= + = 3.0 s 1.01 s 1.99 v 1 is easy to determine since the time t 1 has been found. Using vva 1 0 =+ − , we get v 1 =− = 0 m/s 9.8 m/s 1.01 s 0 s 9.898 m/s 2 ( ) With this value for
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This note was uploaded on 06/17/2008 for the course PHYSICS 2211 taught by Professor Uzer during the Spring '08 term at Georgia Institute of Technology.

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