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2.55.
Model:
We will model the lead ball as a particle and use the constantacceleration kinematic equations.
Visualize:
Note that the particle undergoes free fall until it hits the water surface.
Solve:
The kinematics equation
yyv
tt
a
100
1
0
1
201
0
2
=+ −+
−
()
becomes
−=
+
+
−
−
⇒
=
50
98
0
1
2
1
.(
.
)
(
)
m
0 m
0 m
1
2
m/s
1.01 s
2
Now, once again,
a
v
211
2
1
1
2
1
2
1
1
2
0
−
⇒−=
−
+
=
3.0 s
1.01 s
1.99
v
1
is easy to determine since the time
t
1
has been found. Using
vva
1
0
=+ −
, we get
v
1
=−
−
=
−
0 m/s
9.8 m/s
1.01 s
0 s
9.898 m/s
2
(
)
With this value for
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This note was uploaded on 06/17/2008 for the course PHYSICS 2211 taught by Professor Uzer during the Spring '08 term at Georgia Institute of Technology.
 Spring '08
 UZER
 Acceleration

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