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**Unformatted text preview: **f on the given interval. (b) Find c such that (c) Sketch the graph of f and a rectangle whose area is the same as the area under the graph of f . ). ( c f f ave = ] 2 , [ , ) ( x e x f = [ ] ( 29 ( 29 ( 29 ( 29 1.16 1 2 1 ln 1 2 1 (b) 1 2 1 2 1 2 1 (a) 2 2 2 2 2 ≈ -= ⇔ =-⇔ =-= = = ∫ e c e e c f f e e dx e f c ave x x ave Solution: 1 4 1 c 2 x y x e y =...

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- Spring '08
- varies
- Calculus, Integrals, Mean Value Theorem, 0 Sec