stat 4 hw

# stat 4 hw - basically the probability of picking a red...

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Stat 101-003          Cengiz  Rahmioglu Heller          Penn ID:  37479511 STAT 101 HW 1. (a) 1. The sample space can be defined as: 2. P(blue or red)= P(blue) + P(red) = 0.24 + 0.13 = 0.37   37% 3. P(not green)= 1-P(green)= 1- 0.16 = 0.84   84% (b) 1. Each of the three picking has the sample space defined in part (a) 1. The overall  outcome of the 3 choices are the combinations that can be formed from the results of  the three pickings such as BlueBlueBlue, BlueOrangeRed, OrangeYellowRed etc. 2. P(all three blue) = P(blue) = 0.24 = 0.013824   1.38%
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Unformatted text preview: basically the probability of picking a red M&M from a random M&M package because the results of the two other pickings are independent of the third picking. 4. P(at least one is blue) = 1- P(none of them are blue) = 1 – 0.76 3 = 0.56 56% (c) 1. The sample space is the same sample space defined in part (b) 1. 2. P(all three blue) = 24/100 * 23/99 * 22 /98 = 0.0125 1.25% 3. P(third M&M red)= P(00R)+P(0RR)+P(R0R)+P(RRR)= 13/98 + 13/99*12/98 + 13/100*12/98 + 13/100*12/99*11/98 = 0.13 + 0.01608 + 0.01592 + 0.00177= 0.149 14.9% 4. P(at least one is blue)= 1-P(none of them are blue) = 1- (76/100*76/99*76/98)= 0.548 54.8% 2....
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