Stat 101003
Cengiz Rahmioglu
Heller
Penn ID: 37479511
STAT 101 HW
1.
(a)
1. The sample space can be defined as:
S={Blue, Orange, Green, Yellow, Red, Brown}
2.
P(blue or red)= P(blue) + P(red) = 0.24 + 0.13 = 0.37
37%
3.
P(not green)= 1P(green)= 1 0.16 = 0.84
84%
(b)
1. Each of the three picking has the sample space defined in part (a) 1. The overall outcome(sample
space) of the 3 choices are the combinations that can be formed from the results of the three pickings
such as BlueBlueBlue, BlueOrangeRed, OrangeYellowRed etc.
2. P(all three blue) = P(blue)
3
= 0.24
3
= 0.013824
1.38%
3. P(third M&M red) = P(red) = 0.13
13% The probability of the third M&M to be red is
basically the probability of picking a red M&M from a random M&M package because the
results of the two other pickings are independent of the third picking.
4. P(at least one is blue) = 1 P(none of them are blue) = 1 – 0.76
3
=
0.56
56%
(c)
1. The sample space is the same sample space defined in part (b) 1.
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 Fall '08
 Heller
 Probability, Probability theory, Cengiz Rahmioglu Penn, Rahmioglu Penn ID

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