stat 5 hw

stat 5 hw - Stat 101-003 Heller Cengiz Rahmioglu Penn ID:...

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Stat 101-003 Cengiz Rahmioglu Heller Penn ID: 37479511 STAT 101 HW 1. (a) 1. The sample space can be defined as: S={Blue, Orange, Green, Yellow, Red, Brown} 2. P(blue or red)= P(blue) + P(red) = 0.24 + 0.13 = 0.37 37% 3. P(not green)= 1-P(green)= 1- 0.16 = 0.84 84% (b) 1. Each of the three picking has the sample space defined in part (a) 1. The overall outcome(sample space) of the 3 choices are the combinations that can be formed from the results of the three pickings such as BlueBlueBlue, BlueOrangeRed, OrangeYellowRed etc. 2. P(all three blue) = P(blue) 3 = 0.24 3 = 0.013824 1.38% 3. P(third M&M red) = P(red) = 0.13 13% The probability of the third M&M to be red is basically the probability of picking a red M&M from a random M&M package because the results of the two other pickings are independent of the third picking. 4. P(at least one is blue) = 1- P(none of them are blue) = 1 – 0.76 3 = 0.56 56% (c) 1. The sample space is the same sample space defined in part (b) 1.
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stat 5 hw - Stat 101-003 Heller Cengiz Rahmioglu Penn ID:...

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