stat 6 hw

stat 6 hw - Stat 101-002 Heller Cengiz Rahmioglu Penn ID...

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Stat 101-002          Cengiz  Rahmioglu Heller          Penn ID:  37479511 STAT 101 HW 1.  a) E(X)=μ= ½*P(A is defective) + ½*P(B is defective) = 0.02/2 + 0.1/2 = 0.06   6% b) P(Came from Supplier A|defective)= ½*P(A is defective)/0.06 = 0.01/0.06 = 0.167  16.7% 2. a) E(X)=∑xP(x)= 0(0.05)+1(0.25)+2(0.35)+3(0.15)+4(0.15)+5(0.05) = 2.25 reams of paper b) Var= ∑(x-μ) 2 P(x) = (0-2.25) 2 (0.05)+ (1-2.25) 2 (0.25)+ (2-2.25) 2 (0.35)+ (3-2.25) 2 (0.15)+ (4-2.25) 2 (0.15)+ (5- 2.25) 2 (0.05) =0.253125+0.390625+0.021875+ 0.084375+0.459375+0.378125=1.5575 SD=√Var=1.26 reams of paper c) E(20-X)=20-2.25=17.75 reams of paper. d)SD(20-X)=SD(X)=1.26 reams of paper. e) E(500*X)= 500*E(X)=500*2.25= 1125 pages of papers     SD(500*X)=500*SD(X)= 630 pages of paper 3. a)
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Stat 101-002          Cengiz  Rahmioglu Heller          Penn ID:  37479511 b) P(more than $20)= P($50)+P($100)=0.2+0.1=0.3
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stat 6 hw - Stat 101-002 Heller Cengiz Rahmioglu Penn ID...

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