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# HW10 - Pickering Tracey Homework 10 Due noon Inst Drummond...

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Pickering, Tracey – Homework 10 – Due: Feb 13 2006, noon – Inst: Drummond 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points A 25 . 3 kg mass attached to a spring scale rests on a smooth, horizontal surface. The spring scale, attached to the front end of a boxcar, reads T = 33 . 4 N when the car is in motion. m If the spring scale reads zero when the car is at rest, determine the acceleration of the car, when it is in motion as indicated above. Correct answer: 1 . 32016 m / s 2 . Explanation: Basic Concept: Fictitious forces Inertial/non-inertial frames Solution: In the laboratory frame (which is an inertial frame): The block is accelerating with the car, with an acceleration of a . This requires an external force which must equal m a . Since the tension T is the ONLY available, external force we know that m a = T, so that a = T m = 33 . 4 N 25 . 3 kg = 1 . 32016 m / s 2 Alternative derivation in the acceler- ated frame of the car: The acceleration of the mass in the refer- ence frame of the car is a 0 = 0; on the other hand, the forces acting on the mass are the tension T and the fictitious force F fic = ma , which acts in the direction opposite to the car’s motion. Thus, T - F fic = T - ma = ma 0 = 0 and we get a = T m = 1 . 32016 m / s 2 002 (part 2 of 2) 10 points What would be the reading on the scale if the boxcar were moving at a constant velocity? 1. less than T , but greater than 0 N 2. greater than T 3. 0 N correct 4. T 5. There is not enough information given to tell which is correct. Explanation: The reading will now be zero. The easy way to see this is to let the acceleration be zero, and use this in the equation in part 1. A more sophisticated way to see this is by recognizing that the boxcar is now an inertial frame since it is not accelerating. The block is moving at the same velocity as the boxcar, so the block is at rest in the boxcar’s frame of reference. The net force on the object at rest in an inertial frame is zero. (Newton’s 1st law) 003 (part 1 of 1) 10 points A block of mass m accelerates with accelera-

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