prequiz4

# prequiz4 - Pickering Tracey – Prequiz 4 – Due Oct 2...

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Unformatted text preview: Pickering, Tracey – Prequiz 4 – Due: Oct 2 2005, 6:00 pm – Inst: McCord 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points Calculate the molarity of a solution prepared by dissolving 11 . 5 g NaOH in enough water to make 1 . 5 L of solution. 1. 0.43 M 2. 0.19 M correct 3. 2.3 M 4. 7.6 M Explanation: m NaOH = 11 . 5 g V = 1 . 5 L Molarity is moles solute per liter of solution. We use the molar mass of NaOH (40 g/mol) to convert from grams to moles NaOH: mol NaOH = 11 . 5 g NaOH × 1 mol NaOH 40 g NaOH = 0 . 2875 mol NaOH We divide the moles of NaOH in the solution by the total volume of the solution: M = . 2875 mol NaOH 1 . 5 L solution = 0 . 19 M NaOH 002 (part 1 of 1) 10 points The definition of 1 molar is 1. 1 mole of solute mixed with 1 liter of solvent. 2. 1 mole of solute mixed with 1000 g of solvent. 3. 1 mole of solute in 1 liter of solution. correct Explanation: The definition of molarity is moles solute per liter of solution, so a 1 molar solution would contain 1 mole of solute in 1 liter of...
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## This note was uploaded on 06/23/2008 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas.

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prequiz4 - Pickering Tracey – Prequiz 4 – Due Oct 2...

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