AppendixAUnit8_1Sol

AppendixAUnit8_1Sol - 8. Appendix B: Sample Problem...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
293 8. Appendix B: Sample Problem Solutions The following are solutions to the problems presented in Appendix A. Use these only after attempting the problems on your own.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
294 8.1. Unit 1 - Number Systems, Conversions, Signed Representations and Arithmetic 1. a. 1110110.010111 2 = 1*2 6 + 1*2 5 +1*2 4 + 1*2 2 + 1*2 1 + 1*2 -2 + 1*2 -4 + 1*2 -5 + 1*2 -6 = 118.359375 10 = 001 | 110 | 110.010 | 111 2 = 166.27 8 = 0111 | 0110.0101 | 1100 2 = 76.5C 16 b. 15B.35 16 = 1*16 2 + 5*16 1 +11*16 0 + 3*16 -1 + 5*16 -2 = 347.20703125 10 = 0001 | 0101 | 1011.0011 | 0101 2 = 101 | 011 | 011.001 | 101 | 010 2 = 533.152 8 2. Following Generalized Integer Method and Fraction Method, we have: 923.625 10 = 1110011011.101 2 Integer Quotient Rem. Coeff. Int. Frac. Coeff. 923 ÷ 2 = 461 1 a 0 = 1 461 ÷ 2 = 230 1 a 1 = 1 230 ÷ 2 = 115 0 a 2 = 0 115 ÷ 2 = 57 1 a 3 = 1 57 ÷ 2 = 28 1 a 4 = 1 28 ÷ 2 = 14 0 a 5 = 0 14 ÷ 2 = 7 0 a 6 = 0 7 ÷ 2 = 3 1 a 7 = 1 3 ÷ 2 = 1 1 a 8 = 1 1 ÷ 2 = 0 1 a 9 = 1 0.625 × 2 = 1 0.25 a -1 = 1 0.25 × 2 = 0 0.5 a -2 = 0 0.5 × 2 = 1 0 a -3 = 1 (923) 10 = (1110011011) 2 (0.625) 10 = (0.101) 2 3.
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 5

AppendixAUnit8_1Sol - 8. Appendix B: Sample Problem...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online