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Unformatted text preview: 2 2 2 2 1 4 1 4 1 4 1 =⇔ +== y x y y x y y x Graph is a parabola with vertex of (1/4,1/2) (1/4,1/2) 1 x y y ∆ r 2 y y x r= = y x ( 29 30 5 1 2 1 3 1 5 2 3 ) 2 ( 1 5 4 3 1 4 3 2 2 1 2 π = += += +== ∫ ∫ y y y dy y y y dy y y V By disc method Solutions: Example Two x y 1 = 1= y x y 1 3 x ∆ r i r 1= y x y By washer method ( 29 1 1 1 1 1 ) 1 ( == + = + == i r x y y r ( 29 ( 29 + = + += += + =  + = ∫ ∫ 3 1 3 ln 2 1 3 ln 2 3 1 ln 2 1 2 1 1 1 1 3 1 3 1 2 3 1 2 2 π x x dx x x dx x V...
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 Spring '08
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 Calculus, Euclidean geometry, Ri

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