This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: § 1.2 6. The system is already in row reduced form with leading variables x 1 ,x 3 ,x 4 and free variables x 2 ,x 5 . Let s = x 2 and t = x 5 . The set of solutions is 3 + 7 s t s 2 + 2 t 1 t t : s,t ∈ R . 7. The reduced row echelon form of the system is fl fl fl fl fl fl fl fl x 1 +2 x 2 = 0 x 3 = 0 x 4 = 0 x 5 = 0 fl fl fl fl fl fl fl fl . We have leading variables x 1 ,x 3 ,x 4 ,x 5 and free variable x 2 . If t = x 2 then every solution is  2 t t with t ∈ R . 8. The rref of the system is fl fl fl fl x 2 x 5 = 0 x 4 +2 x 5 = 0 fl fl fl fl . The leading variables are x 2 ,x 4 and the free variables are x 1 ,x 3 ,x 5 . We have x 2 = x 5 x 4 = 2 x 5 Set t = x 5 , then x 2 x 4 x 5 = t 2 t t for t ∈ R where of course x 1 ,x 3 can be equal to anything....
View
Full
Document
This note was uploaded on 06/25/2008 for the course MATH 33a taught by Professor Lee during the Spring '08 term at UCLA.
 Spring '08
 lee

Click to edit the document details