Solution-HW5

Solution-HW5 - MGMT 305 Spring 2007 Assignment 5 Solution...

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Unformatted text preview: MGMT 305 Spring 2007 Assignment 5 Solution (Chapters 13, 14) Chapter 13 3. (16 pts) a. 4(100) 6(85) 5(79) 87 15 x + + = = ( 29 2 1 SSTR k j j j n x x = =- = 4(100 - 87) 2 + 6(85 - 87) 2 + 5(79 - 87) 2 = 1,020 MSTR = SSTR /( k- 1) = 1,020/2 = 510 (4 pts) b. 2 1 SSE ( 1) k j j j n s = =- = 3(35.33) + 5(35.60) + 4(43.50) = 458 MSE = SSE /( n T- k ) = 458/(15 - 3) = 38.17 (4 pts) c. F = MSTR /MSE = 510/38.17 = 13.36 Using F table (2 degrees of freedom numerator and 12 denominator), critical value F(.05; 2, 12) = 3.89. Because F = 13.36 > 3.89, we reject the null hypothesis that the means of the three populations are equal. (4 pts) d. (4 pts) Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatments 1020 2 510 13.36 Error 458 12 38.17 Total 1478 14 Chapter 14 10. (14 pts) a. (3 pts) b. Let x = performance score and y = overall rating. Summations needed to compute the slope and y-intercept are: 2 2752 1177 ( )( ) 1723.73 ( ) 11,867.73 i i i i i x y x x y y x x = = -- = - = 1 2 ( )( ) 1723.73 0.1452 11,867.73 ( ) i i i x x y y b x x -- = = = - 1 78.4667 (.1452)(183.4667) 51.82 b y b x =- =- = 51.82 0.145 y x = + (9 pts) c. 51.82 0.145(225) 84.4 y = + = or approximately 84 (2 pts) 18. (15 pts) a. The estimated regression equation and the mean for the dependent variable are: 1790.5 581.1 3650 y x y = + = The sum of squares due to error and the total sum of squares are 2 2 ( SSE ( ) 85,135.14 SST ( ) 335,000 i i i y y y y = - = = - = Thus, SSR = SST - SSE = 335,000 - 85,135.14 = 249,864.86 (9 pts) b. r 2 = SSR/SST = 249,864.86/335,000 = .746 (4 pts) We see that 74.6% of the variability in We see that 74....
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This note was uploaded on 06/29/2008 for the course MGMT 305 taught by Professor Priya during the Spring '08 term at Purdue University-West Lafayette.

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Solution-HW5 - MGMT 305 Spring 2007 Assignment 5 Solution...

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