!!! Hardy Weinberg Problems - GenotypeFrequencies=p2 2pq q2=1 AlleleFrequencies=p q=1 Problem 1 in 1700 US Caucasian newbo

!!! Hardy Weinberg Problems - GenotypeFrequencies=p2 2pq...

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Genotype Frequencies = p2 + 2pq + q2Allele Frequencies = p + q = 1Examine the following relationships between the Punnett Square and the Hardy-Weinberg Equilibrium and the understanding should help you with the understanding of the following problems. Problem: 1 in 1700 US Caucasian newborns have cystic fibrosis. C for normal is dominant over c for cystic fibrosis. 1. When counting the phenotypes in a population why is cc the most significant?2. What percent of the above population have cystic fibrosis (cc or q2)? 3. From the above numbers you should be able to calculate the expectant frequencies of all the following (assuming a Hardy-Weinberg equilibrium): ALLELE FREQUENCY CALCULATIONS: Why calculate "q" first? ()c = q = ? Why is it now easy to find "p"? ()C = p = ? 5. Now that you know that p =.976 and q = .024. The following genotypes can be found.GENOTYPE FREQUENCY CALCULATIONS: ()CC- Normal homozygous dominate = p2= ?()Cc -carriers of cystic fibrosis = 2pq = ? 6. How many of the 1700 of the population are homozygous Normal? 7. How many of the 1700 in the population are heterozygous (carriers)?  = 1  

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