Homework_2_Solution

Homework_2_Solution - aces we choose only two ace cards...

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Chapter 2 1. (a) S={(r,r),(r,g),(r,b),(g,r),(g,g),(g,b),(b,r),(b,g),(b,b)} (b) S={(r,g),(r,b),(g,r),(g,b),(b,r),(b,g)} 7. (a) the same space : 15 15 2 3 . (b) the event that at least one of the team members is a blue-collar worker : 15 15 6 3 - (c) the event that none of the team members considers himself or herself and independent : 15 4 8. (a) either A or B occur : ( ) ( ) ( ) ( ) 0.5 0.3 0 0.8 P A B P A P B P A B = + - = + - = (b) A occurs but B does not : ( ) ( ) ( ) 0.3 0 0.3 C P A B P A P A B = - = - = (c) both A and B occur : ( ) 0 P A B = (mutually exclusive events) 12. (a) Total number = 50, so 0 1 0.5 100 5 - = (b) 14 10 8 32 + + = , so 0.32 (c) 50 100 1 / 2 2 - 14. ( 29 # 312 470 525 (42 147 86) 25 1057 = + + - + + + = U U P M C 1000 or ( 29 1.057 1 = U U P P M C 32. ( 29 ( 29 1 ! ! + - + b g g b g 36. (a) ( 29 4 52 two cards are both aces / 2 2 = P because there are four aces out of 52 cards. Among four
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Unformatted text preview: aces, we choose only two ace cards. STAT/MATH 418 Solution to Homework 2 (b) ( 29 4 52 two cards have same values / 13 2 2 = P because there are four different shapes and in each shape there are 13 values. Theoretical Exercise 3. ( 29 = = = = I I U U c c F FE FE F E E F S F ( 29 ( 29 ( 29 = = = = I I U U U U U U c c E F E E F E E E F S E F E F 6. (a) c c E F G I I (b) ( 29 c E G F I U (c) E F G U U (f) ( 29 ( 29 ( 29 E F G F E G U U U U U 11. 1 ( ) ( ) ( ) ( ) = +-P E F P E P F P EF 13. ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 φ-= = = = I I I I U U c c c c c P E P EF P E E F P E E E F P EF P EF...
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This note was uploaded on 06/28/2008 for the course MATH 418 taught by Professor Arnold,stevenfdong,yuexiao during the Summer '08 term at Penn State.

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Homework_2_Solution - aces we choose only two ace cards...

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