Mass Relationship in Chemical Reaction (Moles)

Mass Relationship in Chemical Reaction (Moles) - Mass...

This preview shows pages 1–3. Sign up to view the full content.

Mass Relationship in Chemical Reaction Atomic Mass - Mass of an atom in atomic mass units (amu) - Always to four significant figures Mole (n) - One mole of an atom = atomic mass in grams - Ex: One mole of H = 1.008g - Avogadros Number = number of atoms in a mole o 6.022 x 1023 - Moles in Grams o To find how many moles are in a certain amount of grams you use the formula: Moles = ( ) Mass g molar mass - Molar Mass o The mass in grams of 1 mole of units of a substance o Ex: Atomic mass of H: 1.008 amu Molar Mass of H: 1.008g Molar mass of CH4 : 16.04g - Formula mass (molecular mass) o The sum of the atomic masses in a molecule o Ex: Molecular mass of ammonia NH3 (ammonia) N (14.01 x 1) = 14.01g H (1.008 x 3) = 3.024g NH3 = 17.03g - Percent composition of a compound

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
o the percent by m a ss of e ach ele m e nt in a co mpound o Formula:  Percent composition =     molar mass of an element ( ) X moles n molar mass of compound    X  100% o Det er mining Molecular Formula a nd Molar m a ss from gra m s given Chang e gra m s into m oles Det er mine the ratio of the m oles
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern