14 Chemical Equilibrium

# 14 Chemical Equilibrium - Which equation do you use to...

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1 1 If a reaction rate increases by 10 times when the temperature is raised from 20 o C to 30 o C, what is the activation energy for the reaction? -1 -1 8.314 J mol K R 0 o C = 273 K Which equation do you use to determine the activation energy given how the reaction rate changes from one temperature to another? See the example below. 2 1 1 2 1 2 2 1 1 1 A) ln 1 1 B) ln C) either one, A and B are equivalent a a E k k R T T E k k R T T a E RT k = A e 2 2 1 1 2 1 2 2 1 1 1 A) ln 1 1 B) ln a a E k k R T T E k k R T T You can assign the high T, 303 K, to either T 1 or T 2 . If T 1 = 303 K, then T 2 = 293 K, and k 1 = 10 x k 2 2 2 2 2 1 1 A) ln 10 x 303 293 10 x 1 1 B) ln 293 303 a a E k k R E k k R Both give E a = 170 kJ/mol

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2 3 How helpful did you find the “Sand Street Study and Review Guide” in preparing for Exam 01, even though it did not have solutions to the questions? A) Very helpful B) Somewhat helpful C) A bit helpful D) Not helpful E) I didn’t look at it 4 Exam 01 Results See score distribution and commentary on BB. Mean/median = 15/20 = 75% CONGRATULATIONS!!! Half B or higher 35 100% 201 A- to A range Keep up the effort! It pays off!
3 5 Ch 14 Chemical Equilibrium Ch. 14 QRT Homework: 15, 25, 26, 27, 31, 37. Reviews some issues. Introduce some new issues about chemical equilibria.

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14 Chemical Equilibrium - Which equation do you use to...

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