HW 3 solutions (Ch 26,27)

HW 3 solutions(Ch - Physics 6C HW#3 solution 26.30 For a converging lens f is positive We use the thin lens equation 1 p 1 q = 1 f(1 a 1 q = 1 f 1

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Unformatted text preview: Physics 6C HW#3 solution April 25, 2008 26.30 For a converging lens, f is positive. We use the thin lens equation. 1 p + 1 q = 1 f (1) a) 1 q = 1 f- 1 p = 1 20 . cm- 1 40 . cm = 1 40 . cm q = 40.0 cm M =- q p =-1 The image is real, inverted and located 40.0 cm past the lens. b) 1 1 q = 1 f- 1 p = 1 20 . cm- 1 20 . cm = 0 q = ∞ No image is formed. The rays emerging from the lens are parallel to each other. c) 1 q = 1 f- 1 p = 1 20 . cm- 1 10 . cm =- 1 20 . cm q =- 20.0 cm M =- q p = 2.00 The image is upright, virtual and located 20.0 cm in front of the lens. 26.35 a) 1 q = 1 f- 1 p = 1- 32 . cm- 1 20 . cm q =- ( 1 20 . + 1 32 . )- 1 =-12.3 cm The image is 12.3 cm to the left of the lens b) M =- q p = (- 12 . 3) 20 . cm = 0.615 c) 26.44 When you solve a problem with multiple lenses and mirrors, solve thin lens(mirror) equation for each 2 lens(mirror) in order. For example, for two lens problem, solve the thin lens equation(mirror equa- tion) for the first lens(mirror) and the image from...
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This note was uploaded on 07/02/2008 for the course PHYS 6C taught by Professor Staff during the Spring '01 term at UCLA.

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HW 3 solutions(Ch - Physics 6C HW#3 solution 26.30 For a converging lens f is positive We use the thin lens equation 1 p 1 q = 1 f(1 a 1 q = 1 f 1

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