Lab #8 - Experiment #8 Moment of Inertia of a Ring June 18,...

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Experiment #8 – Moment of Inertia of a Ring June 18, 2008 Erin Samplin Group Member: Catie Destio
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Data Table mass (kg) t (s) a (m/s 2 ) α (rad/s 2 ) m(g-a)r (Nm) 0.10 3.9 2 0.1302 5.6587 0.02224 0.15 3.3 0 0.1837 7.9848 0.03318 0.20 2.0 2 0.4902 21.3109 0.04283 0.25 1.9 3 0.5370 23.3448 0.05326 0.30 1.5 1 0.8772 38.1370 0.06157 0.35 1.4 1 1.0060 43.7387 0.07080 radius (r) = 0.023 m Table + Ring mass (kg) t (s) a (m/s 2 ) α (rad/s 2 ) m(g-a)r (Nm) 0.20 10.5 3 0.0180 4 0.7842 0.04500 0.25 8.91 0.0252 0 1.0953 0.05621 0.30 8.39 0.0284 1 1.2353 0.06742 0.35 7.40 0.0365 2 1.5880 0.07860 0.40 7.09 0.0397 9 1.7299 0.08980 0.45 6.79 0.0433 8 1.8861 0.1010 radius 1 (r 1 ) = 0.11275 m radius 2 (r 2 ) = 0.1265 m Graph See attached graphs. Calculations The following equation was used to calculate acceleration, a: Y = V o t + ½at 2 1.0 m = (0 m/s)(t) + ½ (a)(t 2 )
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a = 2 / t 2 For example, the acceleration of the 0.10 kg mass for the table was calculated: a = 2 / (3.92 s) 2 = 0.1302 m/s
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Lab #8 - Experiment #8 Moment of Inertia of a Ring June 18,...

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