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Unformatted text preview: observed). This procedure was first tested on a mixture of NaCl and LiCl, producing wavelengths of 589 nm and 671 nm, proving it to be a mixture of NaCl and LiCl. Unknown mixture 4 produced wavelengths of 590 nm, 624 nm, and 555 nm (and an orange flame). Because these values match those of NaCl (589 nm ~ 590 nm) and CaCl2 (624 nm and 555 nm ~ 553 nm), can be assumed that unknown mixture 4 is a mixture of NaCl and CaCl2. The emission spectrum of hydrogen gas (which was purple in color) was observed. The wavelengths included 415 nm, 438 nm, 491 nm, and 661 nm. A partial energy diagram was made as follows on the attached sheet (a sample calculation of the energy follows): E=hc E=6.626 x 10-34J*s3.00 x 108 ms-14.15 x 10-7m = -4.79 x 10-19J x 1 kJ x (6.022 x 1 023) 1000 J mol = -288.5 kJ * mol-1 Conclusion: It can be concluded that unknown mixture 4 contained NaCl and CaCl2....
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