Exam 1 2003 solutions

# Exam 1 2003 solutions - Exam 1 2003-SOLUTIONS I Multiple...

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Exam 1 --- 2003 ---SOLUTIONS I. Multiple choice 1.b., 2.a., 3.d., 4.e., 5.b. II. a. E = 1136 MeV since γ = 2.294 and E = γ m c 2 (Note: on some browsers Gamma is g and superscripts do not appear.) b. lifetime = τ = γ τ 0 = 2.85x10 -8 sec (longer) c. v τ = 7.68 m d. v 2 ' = (v 1 + |v 2 |) / (1 + v 1 v 2 /c 2 ) = 1.8c/1.81 = 0.994 c (= v 2 measured from beam 1 = 0.994 c) e. Total E in lab = E 1 + E 2 = 2 x 1136 MeV = 2272 MeV III. a. E 1 = -122.4 eV, E 2 = -30.6 eV, E 3 = -13.6 eV b. 3 -> 1 : 108.8 eV, 3 -> 2 : 17.0 eV, 2 -> 1 : 91.8 eV
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• Fall '04
• GaryR.Goldstein
• Physics, Joule, GAMMA, LB&SCR E3 class, LB&SCR E1 class, -SOLUTIONS I. Multiple, 7.68 m

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