3.01 Writing Assignment - Geometry Writing Assignment Distance and Midpoint Formulas Each problem is worth 5 points Total Points 50 Distance Formula 1

# 3.01 Writing Assignment - Geometry Writing Assignment...

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Unformatted text preview: Geometry Writing Assignment: Distance and Midpoint Formulas Each problem is worth 5 points Total Points: 50 Distance Formula 1. Find the distance between the points (-4, 6) and (8, -12).Round your solution to 2 decimal points. d = √(x2-x1)^2 + (y2-y1)^2 √(8-(-4)^2 + (-12-(6))^2 = 2√79 - 17.77638883 = 17.78 2. Find the perimeter of the triangle below. Round your solution to 2 decimal points. d = √(x2-x1)^2 + (y2-y1)^2 dAC=√(3−(−3))^2+(2−6)^2 dAC=√(6)2+(−4)2 dAC=√36+16 dAC=√52 P = √52+ 6+4 P = √4*13+10 P = 10+7.21 = 17.21 dBC = √(3+3)^2+(2-2)^2 dBC = √36+0 dBC = 6 dAB = √(-3+3)^2+(2-6)^2 dAB = √(0)^2+(-4)^2 dAB = √16 dAB = 4 3. Find the length of diagonal XU in the hexagon below. Round your solution to 2 decimal points. U = (-2, 7) X = (2, 2) x1 = -2 x2 = 2 y1 =7 y2=2 (-2-2)^2/4^2 (-4)^2=16 16+25=41 Square root=6.40 4. Find the distance between the two points. Round your solution to 2 decimal points. d= √(4-(-5)^2 + (-1-(-2)^2 d= √(9)^2 + (1)^2 d= √81+1 d= √82 d= approximately 9.06 5. How much longer is CD compared to AB ? Round your solution to 2 decimal points. dCD= √(3-7)^2 +(2--2)^2 dCD= √(-4)^2 + (4)^2 dCD= √ 16 +16 dCD= √32 dCD= approximately 5.66 dAB= √(-8--11)^2 + (8-4)^2 dAB= √(3)^2 + (4)^2 dAB= √ 9 + 16 dAB= √ 25 dAB= 5.00 5.66-5.00 = 0.66 Midpoint Formula 6. Find the coordinates of the midpoint of AB . A (12, -7) and B (-4, 7). M=(x1+x2/2 + y1+y2/2) 12+-4/2 + -7+7/2 =4 Midpoint = (4, 0) 7. M is the midpoint of JK . The coordinates of J are (6, 3) and the coordinates of M are (-3, 4), find the coordinates of K. (6+x)/2 + (3+y)/2)= (-3,4) 1/2( 6+x)=-3 6+x=-6 x=-12 1/2(3+y)=4 3+y=8y=5 K=(-12,5) J=(6,3) K=(-12,5) 8. Find the midpoint of TS . T(-6, 2) S(3, -4) M=(x1+x2/2 + y1+y2/2) (-6+3)/2 + (2+(-4))/2 Midpoint = (-3/2), -1 9. If the midpoint between (x, 6) and (-9, 14) is (8, 10), find the value of x. M=(x1+x2/2 + y1+y2/2) x1=x x2 = -9 y1= 6 y2= 14 x+(-9)/2 = 8 add two - x-9 = 16 add nine - x = 25 10. L is the midpoint of CD . If CL = 1 3 M=(x1+x2/2 + y1+y2/2) (1/3)x + 8 = (2/3)x - 4 (1/3)x + 12 = (2/3)x 12 = (1/3)x 36 = x CL = (1/3)36 + 8 CL = 12 + 8 CL = 20 x + 8 and LD = 2 3 x - 4 , find the length of CD . ...
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