Week3 Calculus - Section 6.1 2 8 12 22 28 360 45 1...

Info icon This preview shows pages 1–4. Sign up to view the full content.

Section 6.1: 2. 1 360 / 45 revolutions 8 3 = 8. 2 4 90 6 90 15 2(15 )=30 and 4(15 )=60 Answer 30 and 60 y x y y + = = = 12. 9 6 3 90 12 84 7 9(7 ) 6 69 and 3(7 ) 21 Answer 69 and 21 z z z z + + = = m = + = g = 22. 180 124 51 179 60 124 51 55 9 3 - - = 28. 34 51 35 34 51/ 60 35/ 3600 34.85972 3 = + + = 42. 203 360 157 - + = g 50. 270 ( )360 n n + 66. 2 2 ( 5 0) ( 2 0) 29 D = - - + - - = 74. 1000(1/ 60) 16.667(360 ) 6000 = = Section 6.2: 4. 2 2 ( 4 0) ( 3 0) 25 5 3 4 3 , , 5 5 4 5 5 4 , , 3 4 3 r Sin Cos Tan Csc Sec Cot θ θ θ θ θ θ = - + + - - = = - - = = = - - = = = 16. 2 2 3 5 0, 0 3(5) 5 0 3 (5 0) ( 3 0) 34 3 34 5 34 3 , , 34 34 5 34 34 5 , , 3 5 3 x y x y y r r Sin Cos Tan Csc Sec Cot θ θ θ θ θ θ + = + = = - = - + - - = - - = = = - - = = =
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

44. 1 15 15 1/ 15 15 Csc Sin Csc Sin α α α α = == = = 52. .4 1/ 1/.4 2.5 Cot Tan Cot Tan β β β β =⌠ = = 56. 0 1& 4: 0 1&3 Thus Quadrant 1 Cos Q Tan Q β β 62. 412 412 360 52 1 and , & are positive Quadrant Sin Cos Tan - = 76. 2 2 2 2 , 3, in Quadrant1 1 ( 3) 1 8 2 2 Tan Sec Tan Sec Tan Tan α α α α α α α = - + = = - - = = Section 6.3: 2. H 8. , , , , k y k SinA CosA TanA z z y z z y CscA SecA CotA k y k = = = = = = 12. 2 2 2 2 2 2 (12) (7) 95 95 7 95 , , 12 12 7 12 95 12 7 95 , , 95 7 95 a b c a a SinA CosA TanA CscA SecA CotA + = = - = = = = = = = 52. 210 1 3 3 , , 2 2 3 2 3 2, , 3 3 SinA CosA TanA CscA SecA CotA θ = = - = - = = - = - =
Image of page 2
74.
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 4
This is the end of the preview. Sign up to access the rest of the document.
  • Fall '06
  • ????
  • Sin, Cot, Tan, Harshad number, Nontotient

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern