PHY 138 - Chapter 1 Solutions

PHY 138 - Chapter 1 Solutions - Problem 1.3 This is easiest...

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Problem 1.3 This is easiest to do by straight-forward substitution [] [] () Time Time Time Length Length g l g l T = = = = = 2 2 2 2 π Problem 1.4 (a) [ ] T L M T ML T ML T ML L T L M T L M T ML mgh mv mv 2 1 2 2 2 2 2 2 2 2 2 2 2 0 2 2 1 2 1 + = + = + = + = The second term doesn’t have the same dimensions due to the presence of the square root operator. (b) [] [ ] [] () LT T L T T L T L T L at v v at v v + = + = + = + = 2 2 0 2 0 The problem with this equation is that the second term had an extra factor of t .
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(c) [][] 2 2 2 2 2 T L T ML v ma v ma = = = (T he left-hand side has a spare factor of m and needs another factor with dimensions of length to be dimensionally correct. Problem 1.7 (a) Three significant digits (b) Four significant digits (c) Three significant digits d) Two significant digits
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PHY 138 - Chapter 1 Solutions - Problem 1.3 This is easiest...

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