Chapter 5
Problem 5.1
The work done by the weight lifter is
! "! "
J
700
m
00
.
2
N
350
#
#
#
Fd
W
.
Problem 5.3
The work done by the tugboat is
! "! "
J
10
50
.
1
m
10
00
.
3
N
10
00
.
5
7
3
3
$
#
$
$
#
#
Fd
W
.
Problem 5.5
(a)
The work done by the force of gravity is
!"
!"
J
3
.
61
60
cos
m
50
.
2
s
m
81
.
9
kg
00
.
5
60
cos
2
#
%
’
(
)
*
+
#
%
#
,
#
mgd
m
W
d
g
.
(b)
The work done by the friction is
! "! "
!"
J
3
.
46
30
cos
m
50
.
2
s
m
81
.
9
kg
00
.
5
436
.
0
30
cos
2

#
%
’
(
)
*
+

#
%

#

#

#
mgd
Nd
fd
W
.
(c)
The work done by the normal force is zero since the normal force and displacement are
perpendicular to each other.
Problem 5.9
(a)
The speed v is found by applying the Work
"
Energy Theorem, to wit,
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!"
s
m
2
kg
10
2.50
J
5000
2
2
2
1
3
2
#
$
#
#
#
#

#
/
m
W
v
mv
K
K
W
K
i
f
.
(b)
The horizontal force exerted on the car is
!"
!"
N
200
m
25.0
J
5000
#
#
#
#
d
W
F
Fd
W
Problem 5.11
The force that each arm exerts is
F
= 355 N and the persons weight is
0
= 700 N then we can use
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 Summer '08
 MEITZLER
 mechanics, Work, Heat, Harshad number, General Conference on Weights and Measures, Kilogram, Standard gravity

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