{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

PHY 138 - Chapter 5 Solutions (Part 1)

# PHY 138 - Chapter 5 Solutions (Part 1) - Chapter!5 Problem...

This preview shows pages 1–3. Sign up to view the full content.

Chapter 5 Problem 5.1 The work done by the weight lifter is ! "! " J 700 m 00 . 2 N 350 # # # Fd W . Problem 5.3 The work done by the tugboat is ! "! " J 10 50 . 1 m 10 00 . 3 N 10 00 . 5 7 3 3 \$ # \$ \$ # # Fd W . Problem 5.5 (a) The work done by the force of gravity is !" !" J 3 . 61 60 cos m 50 . 2 s m 81 . 9 kg 00 . 5 60 cos 2 # % ( ) * + # % # , # mgd m W d g . (b) The work done by the friction is ! "! " !" J 3 . 46 30 cos m 50 . 2 s m 81 . 9 kg 00 . 5 436 . 0 30 cos 2 - # % ( ) * + - # % - # - # - # mgd Nd fd W . (c) The work done by the normal force is zero since the normal force and displacement are perpendicular to each other. Problem 5.9 (a) The speed v is found by applying the Work " Energy Theorem, to wit,

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
!" !" s m 2 kg 10 2.50 J 5000 2 2 2 1 3 2 # \$ # # # # - # / m W v mv K K W K i f . (b) The horizontal force exerted on the car is !" !" N 200 m 25.0 J 5000 # # # # d W F Fd W Problem 5.11 The force that each arm exerts is F = 355 N and the persons weight is 0 = 700 N then we can use
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 4

PHY 138 - Chapter 5 Solutions (Part 1) - Chapter!5 Problem...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online