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Unformatted text preview: Z 1 1 3 1 + x 3 dx, by Comparison Theorem. Question 2 y = 3 x 1 / 2 L = 5 3 Z p 1 + y ( x ) 2 dx = 5 3 Z 1 + 9 xdx = 1 9 2 3 (1 + 9 x ) 3 / 2 5 / 3 = = 2 27 (16 3 / 21 3 / 2 ) = 2 27 63 = 14 3 . 1...
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This note was uploaded on 07/10/2008 for the course MATH 1B taught by Professor Reshetiken during the Spring '08 term at University of California, Berkeley.
 Spring '08
 Reshetiken
 Math, Calculus

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